The metal salt A is blue in color. When salt A is heated strongly over a burner, then a substance B present in it is eliminated and a white powder C is left behind. When a few drops of a liquid D are added to powder C it becomes blue again.
(a) Identify A, B, C, D
Solution
A: CuSO₄. 5H₂0
B: Water for crystallization = 5H₂0
C: CuSO₄
D: H₂O
Chemical equations
CuSO₄.5H₂O ----------> CuSO₄ + 5H₂O
CuSO₄.5H₂O -----------> CuSO₄
CuSO₄ + 5H₂O -------------> CuSO₄ . 5H₂O
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