Q23
A metallic rod of length 'l' is rotated with a frequency v with one end hinged at the centre and the other end at the circumference of a circular metallic ring of radius r, about an axis passing through the centre and perpendicular to the plane of the ring. A constant uniform magnetic field B parallel to the axis is present everywhere. Using Lorentz force, explain how emf is induced between the centre and the metallic ring and hence obtain the expression for it.
Solution
Due to Lorentz force, as the rod rotates, free electrons in the rod travel towards the outer end and are spread around the ring. As a result of the charge separation, an emf is produced across the rod's ends. There is no further flow of electrons at a given emf value, and a steady state is reached.
Induced emf in a Rotating Rod Expression Consider a metallic rod OA of length l rotating with angular velocity w in a uniform magnetic field B, with the plane of rotation parallel to the magnetic field. A rod is thought to be made up of a huge number of tiny components. Consider a small element dx with a distance x from the centre. If v is the element's linear velocity, then the area swept per second equals vdx. The induced emf at the element's ends.